使用FileChooserDialog打开多文件

单文件比较简单，
看到这个函数的原型是这样的：
Glib::SListHandle<Glib::ustring> Gtk::FileChooser::get_filenames ( ) const
因此，就以为要使用这样的变量来进行声明：
Glib::SListHandle<Glib::ustring> filenames =dialog.get_filenames();
for(int i=0;i<filenames.size();i++)
{
//Notice that this is a std::string, not a Glib::ustring.
//std::string filename = dialog.get_filename();
std::cout << "File selected: " << filenames[i] << std::endl;
}
结果发现编译不通过，再仔细看看，Glib::SListHandle并没有重载[]操作符。
再网络上搜索后发现有人和我的问题相同：

That looks like a case where the GLib documentation was automatically
converted to glibmm documentation, but it doesn't really make sense.
SListHandle and ListHandle types are 'intermediate' types that you
shouldn't ever really need to use. They just provide handy
conversions to any of the standard containers. So, you should just be
able to use either std::list<> or std::vector<> or something like
that. So something like the following:

std::list<Glib::ustring> filenames = chooser.get_filenames();

而且，紧跟的一个邮件说明需要使用std::string来声明，就是应该这样：
std::vector<std::string> filenames=chooser.get_filenames();
恩，这样就清楚了。

参考：http://mail.gnome.org/archives/gtkmm-list/2007-May/msg00178.html